Free integral calculator solve indefinite, definite and multiple integrals with all the steps Type in any integral to get the solution, steps and graphStarts from RHS to LHS$\begingroup$ @Adam That is the formula that I have derived in my answer $\endgroup$ – Zev Chonoles Jun 24 '11 at 146 $\begingroup$ I am having trouble seeing the relation My understand of basic math is around grade school level I see what you did, I ahve absolutely zero idea how to derive this like of 30 or so identities but I do have a sheet of paper with them written down and
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What is sec^2x/tanx
What is sec^2x/tanx-) math Prove that the equation Is an identity Sec^4x Tan^4x = Sec^2x Tan^2x Trig Use Trig identities to verify that sec^4(x)Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
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I am trying to express this problem in terms of sin/cos and simplify I couldn't figure out where to go, I tried as best I could I know the answer is 1 but I am more interested to know how to doLegend x and y are independent variables, ;Inizia con la ben nota identità pitagorica # sin^2x cos^2x = 1 # Questo è prontamente derivato direttamente dalla definizione di funzioni trigonometriche di base #sin# e #cos# e il Teorema di Pitagora Dividi entrambi i lati #cos^2x# e otteniamo
· 全国奥林匹克数学竞赛山东赛区二等奖。 中国海洋大学郝文平优秀困难生奖学金。 中国海洋大学优秀学生称号Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorSolve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more
Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more · A different strategy could be rewriting the equation as $$ \sin x=4\cos x1 $$ and squaring (but this may add spurious solutions) $$ 1\cos^2x=16\cos^2x8\cos x1 $$ that gives $$ \cos x(17\cos x8)=0 $$ We know that $\cos x\ne0$ (because the original problem has $\sec x$) and so we remain with $\cos x=8/17$About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us Creators
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Find all solutions of sec^2xtan^2x=3 in the interval 0,2pitan(x) = 1, 1 x = pi/4, 3pi/4, 5pi/4, 7pi/4 Answer by stanbon(757) (Show Source) You can put this solution on YOURIntegral of sec (2x)*tan (2x) Integral example T2 Science Podcast Ep 10 How everyday citizens shape the Indian climate movement Watch later Share · $\tan(2x)$ was easy, as I just had to use the identity $$\tan(2x) = \frac{2\tan x}{1\tan^2x}$$ I'm having a bit of trouble with $\sec(2x)$, however!
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About Press Copyright Contact us Creators Advertise Developers Terms Privacy Policy & Safety How works Test new features Press Copyright Contact us CreatorsWe can find dy/dx by using the product rule If y=uv then dy/dx = u (dv/dx) v (du/dx) In this question u= sin(6x) and v= sec(2x)So du/dx= 6cos(6x) and dv/dx=2sec(2x)tan(2x), using our rules for differentiating trig functionsSubbing this into our product rule formula gives us dy/dx= sin(6x)(2sec(2x)tan(2x)) sec(2x)(6cos(6x))So dy/dx = 2sin(6x)sec(2x)tan(2x)Free math lessons and math homework help from basic math to algebra, geometry and beyond Students, teachers, parents, and everyone can find solutions to their math problems instantly
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Consider The Following Equations 1 Cosec 2x Sec 2x Cosec 2xsec 2x 2 Sec 2x Tan 2x Sec 2xtan 2x 3 Cosec 2x Tan 2x Cot 2x
Purplemath In mathematics, an "identity" is an equation which is always true These can be "trivially" true, like "x = x" or usefully true, such as the Pythagorean Theorem's "a 2 b 2 = c 2" for right trianglesThere are loads of trigonometric identities, but the following are the ones you're most likely to see and useSection 23 Trigonometric Substitutions So far we have seen that it sometimes helps to replace a subexpression of a function by a single variable Occasionally it can help to replace the original variable by something more complicatedI tried squaring it
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0 we have to show that sec(x)2 tan(x)2 − (1 − sin(x)4)sec(x)4 = 0, the left hand side is equivalent to sin ( x)4 − 1 cos ( x)4 sin ( x)2 1 cos ( x)2 = ( sin ( x)2 − 1) ( sin ( x)2 1) ( sin ( x)2 1) cos ( x)2 cos ( x)4 the numerator is equivalent to · tan2x sec2x = 1 So, the original statement is false Sure, there might be values of x for which the original equation works It's solvable, but that doesn't make it true for all x When you started messing with the equation by rewriting it as sines and cosines, I think you goofed the math sin2x/cos2x 1/cos2x = 1 · Since the power on \(\sec x\) is even, rewrite \(\sec^4x=\sec^2x\sec^2x\) and use \(\sec^2x=\tan^2x1\) to rewrite the first \(\sec^2x\) in terms of \(\tan x\) Thus, \(∫\tan^6x\sec^4x\,dx=∫\tan^6x(\tan^2x1)\sec^2x\,dx\) Let \(u=\tan x\) and \(du=\sec^2x\) \(=∫u^6(u^21)\,du\) Expand \(=∫(u^8u^6)\,du\) Evaluate the integral
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